Zalta, E. N. (2014): Frege's Theorem and Foundations for Arithmetic
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Zalta (2014): Edward N. Zalta; Frege's Theorem and Foundations for Arithmetic; Hrsg.: Edward N. Zalta; Reihe: The Stanford Encyclopedia of Philosophy; Band: 2014; Nummer: 4; Hochschule: Stanford University; http://plato.stanford.edu/entries/frege-theorem/index.html; Quellengüte: 5
Attribute
Kürzel | Zalta (2014) |
Quellenart | Web |
Autor(en) | Edward N. Zalta |
Herausgeber | Edward N. Zalta |
Titel | Frege's Theorem and Foundations for Arithmetic |
Reihe | The Stanford Encyclopedia of Philosophy |
Band | 2014 |
Nummer | 4 |
Hochschule | Stanford University |
Fakultät | The Metaphysics Research Lab |
URL | http://plato.stanford.edu/entries/frege-theorem/index.html |
Sprache | Englisch |
Quellengüte | 5 |
Anmerkungen | Archivierte Seite (Winter 2014 Edition, ab 21. Dezember): http://plato.stanford.edu/archives/win2014/entries/frege-theorem/ |
BibTeX
@misc{GlossarWiki:Zalta:2014, author = {Edward N. Zalta}, editor = {Edward N. Zalta}, title = {Frege's Theorem and Foundations for Arithmetic}, howpublished = {http://plato.stanford.edu/entries/frege-theorem/index.html}, institution = {Stanford University -- The Metaphysics Research Lab}, series = {The Stanford Encyclopedia of Philosophy}, volume = {2014}, number = {4}, url = {http://plato.stanford.edu/entries/frege-theorem/index.html}, quality = {5}, note = {Archivierte Seite (Winter 2014 Edition, ab 21. Dezember): http://plato.stanford.edu/archives/win2014/entries/frege-theorem/} }
Nicht-Standard-BibTeX
@web{GlossarWiki:Zalta:2014:ext, author = {Edward N. Zalta}, editor = {Edward N. Zalta}, title = {Frege's Theorem and Foundations for Arithmetic}, institution = {Stanford University -- The Metaphysics Research Lab}, series = {The Stanford Encyclopedia of Philosophy}, volume = {2014}, number = {4}, url = {http://plato.stanford.edu/entries/frege-theorem/index.html}, quality = {5}, note = {Archivierte Seite (Winter 2014 Edition, ab 21. Dezember): http://plato.stanford.edu/archives/win2014/entries/frege-theorem/} }